-4.905x^2-10x+27.7=0

Solution for -4.905x^2-10x+27.7=0 equation:

-4.905x^2-10x+27.7=0

a = -4.905; b = -10; c = +27.7;
Δ = b2-4ac
Δ = -102-4·(-4.905)·27.7
Δ = 643.474
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-\sqrt{643.474}}{2*-4.905}=\frac{10-\sqrt{643.474}}{-9.81}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+\sqrt{643.474}}{2*-4.905}=\frac{10+\sqrt{643.474}}{-9.81}
$